A lift is moving upwards with an acceleration of `2m//sec^(2)`. Inside the lift a `4kg` block is kept on the floor. On the top of it , `3kg` block is placed and again a `2kg` block is kept on the `3kg` . Calculator `:`

`(i)` contact force between `2kg` block and the `3kg` block.
`(ii)` contact force between `4kg` block and floor of the lift.
Draw the free body diagrams properly & take `g=10m//sec^(2)`