If `tanbeta=costhetatanalpha`, then `"tan"^(2)(theta)/(2)`=

If tan beta=costhetatanalpha then tan^2(theta/2) =

If tanbeta = costheta*tanalpha , then tan^2(theta/2) is equal to

If tanbeta = costheta*tanalpha , then tan^2(theta/2) is equal to

If tan theta+1/(tan theta)=2 , then show that tan^(2)theta+1/(tan^(2)theta)= 0

If tan theta + (1)/(tan theta) = 2, then tan^2 theta + (1)/(tan^2 theta) is equal to

Solve tan2 theta=tan((2)/(theta))

If tan theta+(1)/(tan theta)=2, find the value of tan^(2)theta+(1)/(tan^(2)theta)

If tan theta + tan 2theta = tan 3theta , then theta =

Show that [[cos theta,-sin theta],[sin theta,cos theta]]=[[1,-tan(theta)/(2)],[tan(theta)/(2),1]][[1,tan(theta)/(2)],[-tan(theta)/(2),1]]^(-1)