2(x+y)^(2)-9(x+y)-5

If one end of a diameter of the circle 3x^(2) + 3y^(2) - 9 x + 6y + 5 = 0 is (1 ,2) then the other end is _

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1, 2), then the other end is

Factorize :7(2x+5)+3(2x+5)(x+2)y+(x+2)x5a(2x+3y)-2b(2x+3y)8(5x+9y)^(2)+12(5x+9y)

x"@"y=(x+y)^(2) x#y=(x-y)^(2) Find the value of (9#7)"@"(21#5):

Solve for x and y in the following question : 2/(x+2y)+1/(2x-y)+5/9=0, 9/(x+2y)+6/(2x-y)+4=0

If 7x - 15y = 4x + y , find the value of x: y . Hence, use componendo and dividendo to find the values of : (i) (9x + 5y)/(9x - 5y) (iI) (3x^(2) + 2y^(2))/(3x^(2) - 2y^(2))

Find the square root of the expression (4x^2)/(y^2)+(20x)/(y)+13-(30y)/(x)+(9y^2)/(x^2)- (2x)/(y)+5-(3y)/(x) .

Let (x,y) be a variable point on the curve 4x^(2)+9y^(2)-8x-36y+15=0 then min(x^(2)-2x+y^(2)-4y+5)+max(x^(2)-2x+y^(2)-4y+5)