" The factorization of "a^(2)+2ab+b^(2)-c^(2)

Factorize: a^(2)+2ab+b^(2)-c^(2)

The factors of a ^(2) - 2 ab + b ^(2) are (a+b) and (a +b). True or false.

Using factor theorem,show that (a-b),(b-c) and (c-a) are the factors of a(b^(2)-c^(2))+b(c^(2)-a^(2))+c(a^(2)-b^(2))

Using factor theorem,show that a-b,b-C and C-a are the factors of a(b^(2)-c^(2))+b(c^(2)-a^(2))+c(a^(2)-b^(2))

One of the factors of a^(3) - b^(3) - a^(2)b + ab^(2) + a^(2) - b^(2) is

Solve by factorization: x^(2)+2ab=(2a+b)x

factorize : a^2+2ab +b^2-9c^2

If x^(2)+px+1 is a factor of ax^(3)+bx+c then a a^(2)+c^(2)=-ab b) a^(2)+c^(2)ab c) a^(2)-c^(2)=ab d a^(2)-c^(2)=-ab

Factorize: a^(2)+4b^(2)-4ab-4c^(2)