lan40^(@)+2tan10^(@)=tan50^(@)

Prove that tan40^(@) + 2tan10^(@) = tan50^(@)

Prove that tan40^(@) + 2tan10^(@) = tan50^(@)

tan50^(@)-2tan10^(@)=

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , (tan40^(@)+2tan10^(@))*(tan70^(@)-Tan20^(@))=

Without using trigonometric tables , prove that : (i) tan20^(@)tan40^(@) tan45^(@)tan50^(@)tan70^(@)=1 (ii) tan1^(@) tan2^(@)tan60^(@)tan88^(@)tan89^(@)=sqrt(3) (iii) cot5^(@)cot10^(@)cot30^(@)cot80^(@)cot85^(@)=sqrt(3) (iv) 4sin10^(@)sin20^(@)sin30^(@)sec70^(@)sec80^(@)=2

tan20^(@)+2tan50^(@)=

If tan50^(@)-tan40^(@)=k tan10^(@) then the value of k is

tan 10^(@)*tan20^(@)*tan30^(@)*tan40^(@)*tan50^(@)*tan60^@tan70^(@)*tan80^(@)=

tan10^(@) tan 20^(@) tan 30^(@) tan 40^(@) tan 50^(@) tan 60^(@) tan 70^(@) tan 80^(@)=