" If "(1+x+x^(2)+x^(3))^(5)=sum_(k=0)^(15)a_(k)x^(k)" then "sum_(k=0)^(7)a_(2k)=

sum_(k=0)^(5)(-1)^(k)2k

Let (1+x^(2))^(2)(1+x)^(n) = sum_(k=0)^(n+4) a_(k) x^(k) . If a_(1) , a_(2) , a_(3) are in A.P., then n=

Let (1+x^(2))^(2)*(1+x)^(n)=sum_(k=0)^(n+4)a_(k)*x^(k) If a_(1),a_(2) and a_(3) are iun AP, find n.

(1+x^(2))^(2)(1+x)^(n)=sum_(k=0)^(n+4)a_(k)x^(k). If a_(1),a_(2) anda_(3) are in arithmetic progression,then the possible value/values of n is/are a.5 b.4 c.3 d.2

Given (1-x^(3))^(n)=sum_(k=0)^(n)a_(k)x^(k)(1-x)^(3n-2k) then the value of 3*a_(k-1)+a_(k) is

If a=(e^(2 pi i))/(7) and f(x)=A_(0)+sum_(k=1)^(20)A_(k)x^(k) then the value of sum_(r=0)^(6)f(a^(r)x)=n(A_(0)+A_(n)x^(n)+A_(2n)x^(2n)), then the value of n is

If f(x)=sum_(k=0)^(n)a_(k)|x-1|^(k), where a_(i)in R, then