Calculate molecular diameter for a gas if its molar exclued volume is `3.2 pi ml`. (in nenometer) (Take `N_(A) = 6.0 xx 10^(23))`

Molar mass of electron is nearly : (N_(A) = 6 xx 10^(23))

Number of electrons in 36mg of ._8^(18)O^(-2) ions are : (Take N_(A) = 6 xx 10^(23))

Number of electrons in 36mg of ._8^(18)O^(-2) ions are : (Take N_(A) = 6 xx 10^(23))

The number of atoms in 0.1 mol of a tetraatomic gas is ( N_(A) = 6.02 xx 10^(23) mol^(-1) )

The number of atoms in 0.1 mol of a tetraatomic gas is ( N_(A) = 6.02 xx 10^(23) mol^(-1) )

The number of atoms in 0.1 mole of a triatomic gas is (N_(A) = 6.02 xx 10^(23) "mol"^(-1))

Volume of N_(2) at 1 atm, 273 K required to form a monolayer on the surface of iron catalyst is 8.15ml//gm of the adsorbent. What will be the surface area of the adsorbent per gram if each nitrogen molecule occupies 16 xx 10^(-22)m^(2) ? [Take : N_(A)=6xx10^(23) ]

Volume of N_(2) at 1 atm, 273 K required to form a monolayer on the surface of iron catalyst is 8.15ml//gm of the adsorbent. What will be the surface area of the adsorbent per gram if each nitrogen molecule occupies 16 xx 10^(-22)m^(2) ? [Take : N_(A)=6xx10^(23) ]