int(d theta)/(b cos theta+c sin theta)

Integration using rigonometric identities : int(sin theta)/(cos3 theta)+(sin 3 theta)/(cos9 theta)+( sin9 theta)/(cos 27theta)d theta=...+c

int cos 2theta log ((cos theta+sin theta)/(cos theta-sin theta))d theta

int cos2 theta * ln ((cos theta + sin theta) / (cos theta-sin theta)) d theta

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

int(d theta)/((sin theta-2cos theta)(2sin theta+cos theta))=

int(d theta)/(sin theta cos^(3)theta) is equal to

int_(0)^((pi)/(2))(cos theta-sin theta)/((1+cos theta)(1+sin theta))d theta equals -

Evaluate the following integrals: int(2sin 2 theta- cos theta)/(6-cos^2 theta- 4 sin theta)d theta

int cos2 theta log((cos theta+sin theta)/(cos theta-sin theta))=

(sin 3 theta)/(sin theta)-(cos 3 theta)/(cos theta)= A) sin 2 theta B) cos 4 theta C)1D)2