A gaseous hydrocarbon needs 6 times more volume of oxygen `(O_(2))` than itself for complete oxidation. It produces 4 times more `CO_(2)` (by volume) than it's own. What is the formula of the hydrocarbon?

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O_2 for complete oxidation and produces 4 time its own volume of CO_2 is C_(x)H_(y) . The value of y is _________

A gaseous hydrocarbon consumed 5 times its volume of oxygen as for combustion. The volume of CO_(2) produced in the reaction is thrice the volume of hydrocarbon under the same conditions What is the ratio of molecular weight to emperical formula weight of the hydrocarbon?

A gaseous hydrocarbon consumed 5 times its volume of oxygen as for combustion. The volume of CO_(2) produced in the reaction is thrice the volume of hydrocarbon under the same conditions What is the ratio of molecular weight to emperical formula weight of the hydrocarbon?