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A bullet is projected upwards from the top of a tower of height 90 m with the velocity `30 ms^(-1)` making an angle `30^(@)` with the horizontal. Find the time taken by it to reach the ground is `(g=10 ms^(-2))`

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A bullet is projected upwards from the top of a tower of height 90 m with the velocity 30 ms^(-1) making an angle 30° with the horizontal. The time taken by it to reach the ground is (g=10 ms^(-2) )

AAKASH SERIES-MOTION IN A PLANE-NUMERICAL EXERCISE (LEVEL -1)
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  2. A body is projected with velocity 'u' so that the maximum height is th...

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  3. Astone is projected from the ground with a velocity of 20 m/s at angle...

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  4. The horizontal and vertical displacements of a projectile at time t ar...

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  5. A body is projected with velocity 24 ms^(-1) making an angle 30° with ...

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  6. A body projected with velocity 30 ms^(-1) reaches its maximum height ...

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  7. The potential energy of a projectile at its maximum height is equal to...

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  8. Two bodies are thrown at angles theta and (90- theta ) from the sa...

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  9. The minimum and maximum velocities of a projectile are 10ms^(-1) and 2...

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  10. A body is projected with a velocity of 30m/s to have to horizontal r...

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  11. A ball is thrown with velocity 8 ms^(-1) making an angle 60° with the...

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  13. Two bodies are thrown form the same point with the same velocity of p...

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  14. A body is projected at 60^(@) with the horizontal with the velocity of...

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  15. A body is projected horizontally from the top of a tower of height 10m...

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  16. A ball is projected horizontally with a velocity of 5ms^(-1) from the...

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  17. A body is projected horizontally from the top of a tower. When the bod...

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  18. Two tall buildings are 40m apart. With what speed must a ball be throw...

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  19. From the top of a cliff of height 19.6m a ball is projected horizonta...

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  20. A cricket player throws the ball to have the maximum horizontal rang...

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