A vector `sqrt(3)hati + hatj` rotates about its tail through an angle `30^(@)` in clock wise direction then the new vector is

Explanation

The magnitude of `sqrt(3)hati + hatj` is `sqrt(3+1)=2` The angle made by the vector with x-axis is

`tantheta = A_(y)/A_(x) = 1/sqrt(3)`
`therefore theta =30^(@)`
When the given vector rotates 30° in clock wise its direction changes along x - axis but its magnitude does not change.
`therefore` the new vector is `2hati`