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A particle is moving east wards with a v...

A particle is moving east wards with a velocity of 5 `ms^(-1)` In 10 S , the velocity changes to 5 `ms^(-1)` north wards. The average acceleration in this time is

Text Solution

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`veca_(av) =(vec(Deltav))/(Deltat) =(vecv_(f)-vecv_(i))/(Deltat)`

`veca_(av) =(5hati - 5hatj)/10 =(5sqrt(2))/10 = 1/sqrt(2)m//s^(2)`
north -west direction.
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