Home
Class 12
PHYSICS
The resultant of two forces whose magnit...

The resultant of two forces whose magnitudes are in the ratio 3:5 is 28 N. If the angle of their inclination is 60°, then find the magnitude of each force.

Text Solution

Verified by Experts

Let `F_(1)` and `F_(2)` be the two forces.
Then `F_(1) =3x, F_(2) =5x,R = 28N` and `theta=60^(@)`
`R = sqrt(F_(1)^(2) + F_(2)^(2) + 2F_(1)F_(2)cos theta)`
`rArr 28= sqrt(9x^(2) +25x^(2) + 15x^(2))=7x`
`rArr x=28/7=4`
`therefore F_(1) =3 xx 4 =12 N,F_(2) =5 xx 4=20 N`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise SHORT ANSWER TYPE QUESTIONS|6 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise VERY SHORT ANSWER TYPE QUESTIONS|10 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-3 (Circular Motion)|7 Videos

  • MOTION IN A STRAIGHT LINE

    AAKASH SERIES|Exercise very Short answer type question|15 Videos

Similar Questions

Explore conceptually related problems

The resultant of two whose magnitudes are in the ratio 3:5 is 28 N . If the angle of their inclination is 60 ^@ then find the magnitude of each force .

find the resultant of two forces each having magnitude F_0 and angle between them is theta .

The resultant of two forces at right angle is 17N. If the maximum resultant is 23N, the greater force is

Two vectors of equal magnitude P are inclined at some angle such that the difference in magnitude of resultant and magnitude of either of the vectors is 0.732 times either of the magnitude of vectors. If the angle between them is increased by half of its initial value then find the magnitude of difference of the vectors