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Velocity and acceleration of a particle ...

Velocity and acceleration of a particle at time t=0 are `vecu =(2hati + 3hatj)m//s` s and `a = (4hati +2hatj) m//s^(2)` respectively. Find the velocity and displacement of particle at t = 2s.

Text Solution

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Here,
`veca = (4hati + 2hatj) m//s^(2)` is constant.
So, we can apply `vecv =vecu + vecat` and `vecs =vecu t + 1/2vecat^(2)`
Substuting the proper values, we get
`vecv =(2hati + 3hatj) + (2)(4hati + 2hatj) =(10hati + 7hatj) m//s`
Substuting the proper values, we get
`vecv=(2hati + 3hatj) +(2)(4hati + 2hatj) = (10hati + 7hatj)m//s`
and `vecx =(2)(2hati + 3hatj) +1/2(2)^(2) (4hati + 2hatj) = (12hati + 10hatj)m//s`
Therefore, velocity and displacement of particle at t=2s are `(10hati + 7hatj)`m/s and `(12hati + 10hatj)` m respectively.
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