The speed with which a bullent can be fired is `150 ms^(-1)`. Calculate the greatest distance to which it can be projected and also the maximum height to which it would rise .

Explanation

`R=(u^(2) sin 2alpha)/g =((150^(2) sin 90^(@))/9.8) = 2295.1` m
`H_("max") =(u^(2)sin^(2)alpha)/(2g) =((150)^(2) sin^(2)45^(@))/(2 xx 9.8) = 573.97` m