A particle is projected from the origin in X-Y plane. Acceleration of particle in Y direction is a. If equation of path of the particle is `y = ax-bx^(2)`, then find initial velocity of the particle.

Explanation

`y=ax -bx^(2), y=x tan theta -(alphax^(2))/(2u^(2) cos^(2)theta)`
`tan theta =a` and `alpha/(2u^(2) cos^(2) theta) =b, u=sqrt((alpha(1+alpha^(2)))/(2b))`