Home
Class 12
PHYSICS
A ball is throw from the top of a towe...

A ball is throw from the top of a tower of 61 m high with a velocity `24.4 ms^(-1)` at an elevation of `30^(@)` above the horizon. What is the distance from the foot of the tower to the point where the ball hits the ground ?

Text Solution

Verified by Experts


`h=1/2"gt"^(2) -(u sin theta)t rArr t=5` seconds
Also, `d=(u cos theta)t = 105.65` m
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise SHORT ANSWER TYPE QUESTIONS|6 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise VERY SHORT ANSWER TYPE QUESTIONS|10 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-3 (Circular Motion)|7 Videos

  • MOTION IN A STRAIGHT LINE

    AAKASH SERIES|Exercise very Short answer type question|15 Videos

Similar Questions

Explore conceptually related problems

Two towers A and B, each of height 20m are situated a distance 200m apart. A body thrown horizontally from the top of the tower A with a velocity 20 ms^(-1) towards the tower B hits the ground at point P and another body thrown horizontally from the top of tower B with a velocity 30ms^(-1) towards the tower A hits the ground at point Q. if a car starting from rest from P reaches Q in 10 seconds, then the acceleration of the car is (acceleration due to gravity =10 ms^(-2) )

A ball thrown horizontally with velocity v from the top of a tower of height h reaches the ground in t seconds. If another ball of double the mass is thrown horizontally with velocity 3v from the top of another tower of height 4h it reaches the ground in (seconds). In the above problem if the first ball reaches the ground at a horizontal distance d, the second ball reaches the ground at a horizontal distance