A projectile has the maximum range of 500 m. If the projectile is now thrown up on an inclined plane of 30° with the same speed, what is the distance covered by it along the inclined plane ?

Explanation

`R_("max") =u^(2)/g`
`therefore 500 =u^(2)/g` or `u=sqrt(500 g)`
`v^(2)-u^(2) =2gs`
`rArr 0-500g =2 xx (g sin 30^(@))xx x`
`x=500 m`