A particle is projected from a tower as shown in figure, then find the distance from the foot of the tower where it will strike the ground. (g = 10 `m//s^(2)`)

Explanation

`s=ut + 1/2at^(2)`
`1500 = 500/3 sin 37 + 1/2 10 xx t^(2)`
`1500 = 500/3 xx 3/5 t + 5t^(2)` `300 = 20t + t^(2)`
On solving, t=10 s
`therefore` Horizontal distance `=u cos theta`, T
`=500/3 xx 4/5 xx 10 = 4000/3` m