Two particle move in a unifrom gravitational field with an acceleration "g". At the initial moment the paricles were located at one point and moved with velcoities `u_(1) = 3.0 ms^(-1)` and `u_(2) = 4.0 ms^(-1)` horizontally in opposite directions. Find the distance between the patricles at the moment when their their velocity vectors become mutually perpendicular .

Explanation

`t= sqrt((u_(1)u_(2))/g), x=(u_(1) + u_(2))t`

=0.48 m