What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth = 6400 km.)

Explanation

The earth completes one rotation in 24 hour. Its angular velocity.
`omega =(2piN)/t =(2pi xx t)/(24 xx 60 xx 60) = pi/(43,200) "rad"s^(-1)`
`R = 6.4 xx 10^(6)` m
The linear velocity.
`v=Romega =6.4 xx 10^(6) xx pi/(43,200) = 465.5` m/s