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Two boys are standing at the ends A and ...

Two boys are standing at the ends A and B of a ground where AB = a. They boy at B starts runing in a direction perpendicular to AB with velocity `v_(1)` . The boy at A starts runing simultaneously with velocity v and catches the other in a time t, where t is

A

`a/sqrt(v^(2) + v_(1)^(2))`

B

`a/(v+v_(1))`

C

`a/(v-v_(1))`

D

`sqrt(a^(2)/(v^(2)-v_(1)^(2)))`

Text Solution

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The correct Answer is:
D
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