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A body is projected with velocity 'u' so...

A body is projected with velocity 'u' so that the maximum height is thrice the horizontal range. Then the maximum height is

A

`(72u^(2))/(145 g)`

B

`6/sqrt(145) u^(2)/g`

C

`u^(2)/(2g)`

D

`145/72 u^(2)/g`

Text Solution

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The correct Answer is:
A
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