The distance between the tew slits in a Young's double slit experiment is d and the distance of the screen from the plane of the slits is b, P is a point on the screen directly infront of one of the slits. The path difference between the waves arriving at P from the two slits is

Options

A. `(d^(2))/(b)`
B. `(d^(2))/(2b)`
C. `(2d^(2))/(b)`
D. `(d^(2))/(4b)`

Answer

B

Explanation

Distance between 2 slit(b) is d
Distance from screen from plane (D) is b
When wave will reach at point P on the screen then path difference is
Path difference=
D
yd
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