Two light waves having the same waveleng...

Two light waves having the same wavelength `lambda` in vocume are in phase initially. Then the first ray travels a path of length `L_(1)` through a medium of refractive index `mu_(1)`. The second ray travels a path of length `L_(2)` through a medium of refractive index `mu_(2)`. The two waves are then combined to observe interference effects. The phase difference between the two when they interfere, is

`(2pi)/(lambda)(L_(1) - L_(2))`

`(2pi)/(lambda)(mu_(1)L_(1) - mu_(2)L_(2))`

`(2pi)/(lambda)(mu_(2)L_(1) - mu_(1)L_(2))`

`(2pi)/(lambda)[(Li)/(mu_(1)) - (L_(2))/(mu_(2))]`

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