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Light of wavelength lambda in air enters...

Light of wavelength `lambda` in air enters medium of refractive index μ. If two points in this medium lie along the path of this light at a distance x, then phase difference `phi_(0)` between these two points is

A

`phi_(0) = (1)/( μ)((2pi)/(lambda)) x`

B

`phi_(0) = μ((2pi)/(lambda)) x`

C

`phi_(0) = ( μ-1)((2pi)/(lambda_(0))) x`

D

`phi_(0) = (1)/(( μ-1))((2pi)/(lambda_(0))) x`

Text Solution

Verified by Experts

The correct Answer is:
B
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