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In Young's double slit experiment the di...

In Young's double slit experiment the distance between slits is `2 xx 10^(-3)m`, the distance between screen and slits is 200 cm. When the light of wave length `5000 A^(@)` is used, then the fringe width on the screen will be

A

2mm

B

0.05mm

C

1mm

D

0.5mm

Text Solution

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The correct Answer is:
D
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In Young.s double slit experiment the separation d between the slits is 2mm, the wavelength lambda of the light used is 5896 A^(0) and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0.20^(0) . To increase the fringe angular width to 0.21^(0) (with same lambda and D) the separation between the slits needs to be changed to

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