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A square coil of side 10 cm consists of ...

A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of `30^@` with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?

Text Solution

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It is given that each side of square coil `l = 10 cm = 0.1 m,` hence area `A = l^2 = (0.1)^(2) = 0.01 m^2`
`N = 20 , I = 12 A , theta = 30^@ and B = 0.80 T`
`:.` Torque `tau = N B A I sin theta = 20 xx 0.8 xx 0.01 xx 12 xx sin 30^@`
`= 20 xx 0.8 xx 0.01 xx 12 xx 1/2 = 0.96 N m^(-1)`.
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