(a) Derive the expression for the magnetic field due to a current carrying coil of radius r at a distance x from the centre along the X-axis. (b) A straight wire carrying a current of 5 A is bent into a semicular arc of radius 2 cm as shown in the fig. FInd th magnitude and direction of the magnetic field at the centre of the arc.
Text Solution
Verified by Experts
The correct Answer is:
(b) `7.8 xx 10^(-5) T ox`
Topper's Solved these Questions
MOVING CHARGES AND MAGNETISM
U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION C)|1 Videos
The magnetic field at the centre of current carrying coil is
A straight wire carrying a current 10 A is bent into a semicircular arc of radius 5 cm . The magnitude of magnetic field at the center is
Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R on its axis is
The magnetic field at the centre of the current carrying coil
A circular loop of radius 9.7 cm carries a current 2.3 A. Obtain the magnitude of the magnetic field at the centre of the loop .
The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at distance 'a' from centre of the coil and perpendicular to the axis of coil is
A straight wire carrying a current of 13 A is bent into a semi-circular arc of radius 2 cm as shown in figure. The magnetic field is 1.5 xx 10^(-4)T at the centre of arc, then the magnetic field due to straight segment is
What will be magnetic field at centre of current carrying circular loop of radius R?
U-LIKE SERIES-MOVING CHARGES AND MAGNETISM -SELF ASSESSMENT TEST (SECTION D)
