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(a) Derive the expression for the magnet...

(a) Derive the expression for the magnetic field due to a current carrying coil of radius r at a distance x from the centre along the X-axis.
(b) A straight wire carrying a current of 5 A is bent into a semicular arc of radius 2 cm as shown in the fig. FInd th magnitude and direction of the magnetic field at the centre of the arc.

Text Solution

Verified by Experts

The correct Answer is:
(b) `7.8 xx 10^(-5) T ox`
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Knowledge Check

  • The magnetic field at the centre of current carrying coil is

    A
    `(mu_(0)ni)/(2r)`
    B
    `(mu_(0))/(2pi)(ni)/r`
    C
    `(mu_(0)ni)/(4r)`
    D
    `mu_(0)ni`

  • A straight wire carrying a current 10 A is bent into a semicircular arc of radius 5 cm . The magnitude of magnetic field at the center is

    A
    `1.5xx10^(-5)T`
    B
    `3.14xx10^(-5)T`
    C
    `6.28xx10^(-5)T`
    D
    `19.6xx10^(-5)T`

  • Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R on its axis is

    A
    `10sqrt(10)`
    B
    `20sqrt(10)`
    C
    `2sqrt(10)`
    D
    `sqrt(10)`

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