Calculate the value of Bohr's radius. Given that mass of electron `= 9.11 xx 10^(-31)` kg, Planck's constant `h=6.63 xx 10^(-34)` J s and electronic charge is `1.60 xx 10^(-19)` C.

Explanation

Given that for electrones `e= 1.60 xx 10^(-19) C, m_(c) =9.11 xx 10^(-31)`kg and `h=6.63 xx 10^(-34)` J s.
In ground state in an hydrogen atom the electron is in state n =1. Hence, radius of electron orbit (ie. Bohr.s radius) is
`a_(0) =( in_(0) h^(2))/( pi m e^(2)) .(1)^(2) = (8.85xx 10^(-12) xx (6.63 xx 10^(-34))^(2))/(3.14 xx 9.11 xx 10^(-31) xx (1.60 xx 10^(-19))^(2)) = 5.3 xx 10^(-11) m`