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Two capacitors of capacitances C(1) and ...

Two capacitors of capacitances `C_(1)` and `C_(2)` are connected in parallel. If a charge Q is given to the combination, the ratio of the charge on the capacitor `C_(1)` to the charge on `C_(2)` will be

A

`(C_(1))/(C_(2))`

B

`sqrt((C_(1))/(C_(2))`

C

`sqrt((C_(2))/(C_(1))`

D

`(C_(2))/(C_(1))`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `(C_(1))/(C_(2))`
[Hint: When two capacitors are connected in parallel, potential difference across them is same i.e., `V_(1)=V_(2)=V`(say), So `(Q_(1))/(Q_(2))=(C_(1)V_(1))/(C_(2)V_(2))=(C_(1)V)/(C_(2)V)=(C_(1))/(C_(2)).`]
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