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A hydrogen atom is in its third excited ...

A hydrogen atom is in its third excited state.
(a) How many spectral lines can be emitted by it before coming to the ground state ? Show these transitions in the energy level diagram.
(b) In which of the above transitions will the spectral line of shortest wavelength be emitted ?

Text Solution

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The correct Answer is:
a
(a) The hydrogen atom is in its third excited state i.e., it is in n= 4 state. Before coming to ground state (n = 1) the total number of spectral lines is `(n(n-1))/2=(4xx3)/2=6`. The transitions corresponding to these six lines are shown in the energy level diagram here.
(b) In transition (4 - 1) energy difference and frequency of emitted radiation is maximum and as a result we get a spectral line of shortest wavelength.
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