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Three resistances of 2 Omega, 3 Omega an...

Three resistances of `2 Omega, 3 Omega and 6 Omega` are first connected in series and the equivalent resistance is found to be……… Then the three resistances are connected in parallel Now its equivalent resistance is………

Text Solution

Verified by Experts

`11 Omega, 1 Omega`
In series `R_s=2+3+6=11 Omega`
In parallel `1/R_p=1/2+1/3+1/6=1/1 implies R_p=1 Omega`
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Knowledge Check

  • Three resistors of 1 Omega, 2 Omega and 3 Omega are connected in parallel. The combined resistance of 3 resistors should be

    A
    greater than `3 Omega`
    B
    lesser than `1 Omega`
    C
    equal to `2 Omega`
    D
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  • The resistors of resistances 2 Omega, 4 Omega and 8 Omega are connected in parallel, then the equivalent resistance of the combination will be

    A
    `(8)/(7) Omega`
    B
    `(7)/(8)Omega`
    C
    `(7)/(4)Omega`
    D
    `(4)/(9)Omega`
  • The resistors of values 3 Omega,6 Omega and 15Omega are connected in parallel. What will be equivalent resistance in the circuit?

    A
    `0.8`
    B
    `1.4`
    C
    `2.1`
    D
    `1.7`
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