Home
Class 10
PHYSICS
Assertion (A): Flow of 6.25 times 10^18 ...

Assertion (A): Flow of `6.25 times 10^18` electrons per second through a cross section of a conductor constitutes an electric current of one ampere.
Reason ( R): Charge on an electron `=1.6 times 10^-18 C`

A

Both (A) and (R ) are true and (R ) is correct explanation of the assertion

B

Both (A ) and ( R) are true but (R ) is not the correct explanation of the assertion.

C

(A ) is true but (R ) is false

D

(A) is false but (R ) is true

Text Solution

Verified by Experts

`I=(n e)/t implies n=(I t)/e= (1 times 1)/(1.6 times 10^-19)=6.25 times 10^18`
Promotional Banner

Topper's Solved these Questions

  • ELECTRICITY

    U-LIKE SERIES|Exercise VERY SHORT ANSWER QUESTIONS|54 Videos

  • ELECTRICITY

    U-LIKE SERIES|Exercise SHORT ANSWER QUESTION|44 Videos

  • ELECTRICITY

    U-LIKE SERIES|Exercise FILL IN THE BLANKS|9 Videos

  • CBSE SAMPLE QUESTION PAPER 2019 - 20 (SOLVED)

    U-LIKE SERIES|Exercise SECTION A|10 Videos

  • LIGHT - REFLECTION AND REFRACTION

    U-LIKE SERIES|Exercise LONG ANSWER QUESTIONS|14 Videos

Similar Questions

Explore conceptually related problems

How many electrons per second pass through a cross-section of copper wire carrying 10^(-16) A current ?

A flow of 10^7 electrons per second in a conducting wire constitutes a current of

How many electrons should flow per seconds to constitute a current of magnitude one ampere ?

n electrons flow through a cross-section of a conductor in time t . If the charge on an electron is e , write an expression for the current in the conductor.

The number of electrode passing per second through a cross-section of copper wire carrying 10^(-6) ampere: