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A given length of a wire is doubled on i...

A given length of a wire is doubled on itself. By what factors does the resistance of the wire change?

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When a given length of wire is doubled on itself, its new length `L.=L/2` and new cross section area A.=2A Hence its new resistance `R.=(rho L.)/(A.)= (rho(L/2))/((2A))=1/4 (rho L)/A=R/4`
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