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CuSO(4).5H(2)O is blue in colour while C...

`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless, why ?

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In `CuSO_(4).5H_(2)O`, water acts as ligand as a result it causes crystal field splitting. Hence d-d transition is possible in `CuSO_(4).5H_(2)O` and shows colour. In the anhydrous `CuSO_(4)` due to the absence of water (ligand), crystal field splitting is not possible and hence no colour.
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