" 13."2y^(3)-5y^(2)-19y+42

y^(3)-2y^(2)-29y-42

The factors of 2y^3 - 5y^2 - 19y + 42 are :

2y ^ (4) + y ^ (3) -14y ^ (2) -19y-6

Divide 36x^(2)y^(5)+42xy^(3)-24x^(3)y^(2)-12y^(5) by -6y^(2) .

Find the separate equation of the following pair of straight lines 2x^(2)-xy-3y^(2)-6x+19y-20=0

The acute angle between the line represented by 2x^(2)-xy-3y^(2)-6x+19y-20=0 is

The point of intersection of the lines represented by 2x^(2)-xy-3y^(2)-6x+19y-20=0 is

From a point on x+2y-7=0 tangents are drawn to curve 13(x^(2)+y^(2)-2x+1)=(2x+3y-1)^(2) are perpendicular then the point is (a)(19,13) (b) (-19,13) (c) (19,-13) (d)(-19,-13)

Factorise : y^3 - 2y^2 - 29y - 42 .