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Find the value of cos (-171 0^(@))...

Find the value of `cos (-171 0^(@))`

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We know, for any natural number n`cos(2npi +x) = cos x`. So,
`cos(-1710^@) =cos(5**2pi + (-1710^@))`
`cos(1800^@-1710^@) = cos90^@ = 0`
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