Prove that:`tan4x=(4tanx(1-tan^2x))/(1-6tan^2x+tan^4x)`

Explanation

To prove that \( \tan(4x) = \frac{4\tan(x)(1 - \tan^2(x))}{1 - 6\tan^2(x) + \tan^4(x)} \), we will start with the double angle formula for tangent.

### Step 1: Use the double angle formula for tangent
We know that:
\[ \tan(2x) = \frac{2\tan(x)}{1 - \tan^2(x)} \]
Now, we can express \( \tan(4x) \) as:
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