Find `sin``x/2``,cos``x/2`and `tan``x/2` of the following : `tanx=-4/3, `x in quadrant II`

Explanation

To find \( \sin \frac{x}{2} \), \( \cos \frac{x}{2} \), and \( \tan \frac{x}{2} \) given that \( \tan x = -\frac{4}{3} \) and \( x \) is in quadrant II, we will follow these steps:

### Step 1: Determine the Quadrant for \( \frac{x}{2} \)
Since \( x \) is in quadrant II, it means that \( 90^\circ < x < 180^\circ \). Dividing the entire inequality by 2 gives:
\[ 45^\circ < \frac{x}{2} < 90^\circ \]
This indicates that \( \frac{x}{2} \) is in quadrant I, where all trigonometric functions are positive.
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