Convert of the complex number in the polar form: `sqrt(3)+i`

Explanation

Here, `z = -sqrt(3) + i`

Comparing it with polar form, we get,

`rcostheta = sqrt3 and rsintheta = 1`

Squaring and adding these two terms, we get,

`r^2cos^2theta+r^2sin^2theta = 4 `

`r^2(cos^2theta+sin^2theta) = 4`

`r^2 = 4=> r = 2`

So, modulus `|r|` is `2`.

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