Find real `theta` such that `(3+2isintheta)/(1-2isintheta)`is purely real.

Explanation

To find the real `theta` such that \(\frac{3 + 2i \sin \theta}{1 - 2i \sin \theta}\) is purely real, we can follow these steps:

### Step 1: Set up the expression
Let \( z = \frac{3 + 2i \sin \theta}{1 - 2i \sin \theta} \).

### Step 2: Multiply by the conjugate
To eliminate the imaginary part in the denominator, multiply both the numerator and the denominator by the conjugate of the denominator:
\[
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