Solve the equation :`x^2-2x+3/2=0`

Explanation

We know the roots of the quadratic equation `Ax^2+Bx+C=0 `are

`x=(−B±sqrt(B^2−4AC))/(2A)`

​​The given equation is
`x^2-2x+3/2=0`

for the given equation, `B^2−4AC=(-2)^2−4(1)(3/2)=−8`

So the roots are

`x=(-(-4)±sqrt(−8))/(2*2)`

`x=((4)±2sqrt(-2))/(4)`

​​`x=(4±2sqrt(2)​i)/4`

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