Solve the equation :`21 x^2-28 x+10=0`

Explanation

To solve the quadratic equation \( 21x^2 - 28x + 10 = 0 \), we will follow these steps:

### Step 1: Identify coefficients
We start by identifying the coefficients \( a \), \( b \), and \( c \) from the standard form of a quadratic equation \( ax^2 + bx + c = 0 \).

Here,
- \( a = 21 \)
- \( b = -28 \)
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