Find the `13^(t h)`term in the expansion of `(9x-1/(3sqrt(x)))^(18),x!=0`

Explanation

To find the 13th term in the expansion of \( (9x - \frac{1}{3\sqrt{x}})^{18} \), we will use the Binomial Theorem, which states that the general term \( T_{r+1} \) in the expansion of \( (a + b)^n \) is given by:

\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]

### Step-by-Step Solution:

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