The sum of the coefficients of the first three terms in the expansion of`(x-3/(x^2))^m ,x!=0,`m being a natural number, is 559. Find the term of the expansion containing `x^3`.

Explanation

To solve the problem, we need to find the value of \( m \) such that the sum of the coefficients of the first three terms in the expansion of \( \left( x - \frac{3}{x^2} \right)^m \) equals 559. Then, we will find the term of the expansion that contains \( x^3 \).

### Step 1: Write the first three terms of the expansion

The binomial expansion of \( (a + b)^n \) is given by:
\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]
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