If the `p^(t h)`,`q^(t h)`and `r^(t h)`terms of a GP are a, b and c, respectively. Prove that `a^(q-r)b^(r-p)c^(p-q)=1`.

Explanation

To prove that \( a^{(q-r)} b^{(r-p)} c^{(p-q)} = 1 \) given that \( a, b, c \) are the \( p^{th}, q^{th}, \) and \( r^{th} \) terms of a geometric progression (GP), we can follow these steps:

### Step 1: Define the terms of the GP
The \( n^{th} \) term of a GP can be expressed as:
\[ T_n = A \cdot R^{n-1} \]
where \( A \) is the first term and \( R \) is the common ratio.
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