The sum of first three terms of a G.P. is `(39)/(10)` and their product is 1. Find the common ratio and the terms.

Explanation

Let `a/r`, a, ar be first three term of the given G.P

∴`a/r`+a+ar=3910 .... (1)

and` a/r`+a+ar=1

⇒`a^3`=1⇒a=1 ........(2)

Substituting the value of 'a' from (2) in(1),

`1/r`+1+r=`39/10`

⇒10+10r+10`r^2`=39r

⇒10`r^2`−29r+10=0

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