Home
Class 11
MATHS
Find the sum of odd integers from 1 to ...

Find the sum of odd integers from 1 to 2001.

Text Solution

AI Generated Solution

To find the sum of odd integers from 1 to 2001, we can follow these steps: ### Step 1: Identify the sequence of odd integers The odd integers from 1 to 2001 form an arithmetic progression (AP) with the first term \( a = 1 \) and the common difference \( d = 2 \). The series is: \[ 1, 3, 5, 7, \ldots, 2001 \] ### Step 2: Determine the number of terms (n) To find the number of terms in the series, we can use the formula for the \( n \)-th term of an AP: ...
Promotional Banner

Topper's Solved these Questions

  • SEQUENCES AND SERIES

    NCERT ENGLISH|Exercise EXERCISE 9.3|32 Videos
  • SEQUENCES AND SERIES

    NCERT ENGLISH|Exercise EXERCISE 9.1|14 Videos
  • SEQUENCES AND SERIES

    NCERT ENGLISH|Exercise SOLVED EXAMPLES|24 Videos
  • RELATIONS AND FUNCTIONS

    NCERT ENGLISH|Exercise EXERCISE 2.3|5 Videos
  • SETS

    NCERT ENGLISH|Exercise EXERCISE 1.5|7 Videos

Similar Questions

Explore conceptually related problems

Find the sum of integers from 1 to 100 that are divisible by 2 or 5.

Find the sum of all odd integers between 2 and 100 divisible by 3

Find the sum of all odd integers between 2 and 100 divisible by 3

Find the (i) sum of those integers between 1 and 500 which are multiples of 2 as well as of 5. (ii) sum of those integers from 1 to 500 which are multiples of 2 as well as of 5. (iii) sum of those integers from 1 to 500 which are multiples of 2 or 5.

Find the sum of the integers between 1 and 200 which are multiples of 3.

The sum of the integers from 1 to 100 which are not divisible by 3 or 5 is

{:("Quantity A","Quantity B"),("The sum of the consecutive","34 less than the sum of the"),("integers from 2 to 15","consecutive integers from 1 to 17"):}

Show that the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667.

Find the number of integers between 1 and 100000 having the sum of the digits 18.

Find the center of odd integers between 30000 and 80000 in which no digit is repeated.

NCERT ENGLISH-SEQUENCES AND SERIES-EXERCISE 9.2
  1. Sum of the first p, q and r terms of an A.P are a, b and c, respectiv...

    Text Solution

    |

  2. Insert five numbers between 8 and 26 such that the resulting sequence...

    Text Solution

    |

  3. A mail starts repaying a loan as first instalment of Rs. 100. If he i...

    Text Solution

    |

  4. The difference between any two consecutive interior angles of a polyg...

    Text Solution

    |

  5. Between 1 and 31, m numbers have been inserted in such a way that the...

    Text Solution

    |

  6. If the sum of first p terms of an A.P. is equal to the sum of the fir...

    Text Solution

    |

  7. If the sum of n terms of an A.P. is 3n^2+5and its m^(t h)term is 164,...

    Text Solution

    |

  8. The ratio of the sum of m and n terms of an A.P. is m^(2) :n^(2). Show...

    Text Solution

    |

  9. If (a^n+b^n)/(a^(n-1)+b^(n-1))is the A.M. between a and b, then find t...

    Text Solution

    |

  10. If the sum of n terms of an A.P. is (p n+q n^2) , where p and q are...

    Text Solution

    |

  11. The sums of n terms of two arithmetic progressions are in the ratio 5...

    Text Solution

    |

  12. If the sum of a certain number of terms of the A.P. 25, 22, 19.... is...

    Text Solution

    |

  13. Find the sum to n terms of the A.P., whose k^(t h)term is 5k + 1.

    Text Solution

    |

  14. How many terms of the A.P. 6, -(11)/2,-5,dotdotdotare needed to give...

    Text Solution

    |

  15. In an A,P if the pth term is (1)/(q) and q^(th) terms is (1)/(p). Prov...

    Text Solution

    |

  16. Find the sum of all natural numbers lying between 100 and 1000, which...

    Text Solution

    |

  17. In an A.P., the first term is 2 and the sum of the first five terms i...

    Text Solution

    |

  18. Find the sum of odd integers from 1 to 2001.

    Text Solution

    |