Find equation of the line which is equidistant from parallel lines `9x" "+" "6y" "" "7" "=" "0` and `3x" "+" "2y" "+6" "=" "0` .

Explanation

Given lines are

`9x+6y-7= 0.....(1)`

` 3x+2y+6= 0....(2)`

Let p(h,k) be the arbitrary point that is equidistant from lines (1) and (2),
the perpendicular distance of p(h,k) from line (1) is given by

`d1​=(​∣9h+6k−7∣​)/((9)^6+(12)^2)`

`=(​∣9h+6k−7∣)/sqrt(117)`

​`=(​∣9h+6k−7∣​)/(3sqrt(13))`


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